3782: Ternary Calculation
Problem Description
ZOJ-3782
Solution in Java
package ZOJ;
/**
* @author Teerapat Phokhonwong
* @Onlinejudge: ZOJ
* @Problem: 3782 Ternary Calculation
* @Link: http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=5269
* @Timelimit: 2 Seconds
* @Status: Accepted
* @Submission: 2015-06-07 04:15:37
* @Runtime: 136 ms
* @Solution:
* @Note:
*/
import java.util.Scanner;
public class P3782_Ternary_Calculation {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int t = sc.nextInt();
for (int i = 0; i < t; i++) {
int number1 = sc.nextInt();
String operator1 = sc.next();
int number2 = sc.nextInt();
String operator2 = sc.next();
int number3 = sc.nextInt();
int answer = 0;
if(operator1.equals("*") || operator1.equals("/") || operator1.equals("%")){
switch(operator1){
case("*"): answer=number1*number2;
break;
case("/"): answer=number1/number2;
break;
case("%"):answer=number1%number2;
break;
}
switch(operator2){
case("+"): answer = answer+number3;
break;
case("-"): answer = answer-number3;
break;
case("*"): answer = answer*number3;
break;
case("/"): answer = answer/number3;
break;
case("%"):answer = answer%number3;
break;
}
}
else if(operator2.equals("*") || operator2.equals("/") || operator2.equals("%")){
switch(operator2){
case("*"): answer=number2*number3;
break;
case("/"): answer=number2/number3;
break;
case("%"):answer=number2%number3;
break;
}
switch(operator1){
case("+"): answer = number1+answer;
break;
case("-"): answer = number1-answer;
break;
}
}
else{
switch(operator1){
case("+"): answer = number1+number2;
break;
case("-"): answer = number1-number2;
break;
}
switch(operator2){
case("+"): answer = answer+number3;
break;
case("-"): answer = answer-number3;
break;
}
}
System.out.println(answer);
}
}
}